Initval:step:endval - In this, the index increments by the value step on each iteration.
Initval:endval - Here, you need to specify the index variable from initval to endval by 1.Īnd the statement executes until the index is greater than endval. Values: There can be following forms of value: In other words, the result contains the non zero elements or non-empty the condition becomes true, otherwise false. In the while loop, the program statement repeatedly executes as long as the expression becomes false. It executes the statement continuously until the specific condition becomes false. Also, this is very verbose, there is a two line answer to your problem but without actually using MATLAB I can't think it up (there was a time when I would have known it off the top of my head, but alas, that day is no more).The while loop works on the simple phenomena. I don't have access to MATLAB and can't play around to make sure it is correct. Huge Note! This is untested but provides the general gist of what you need to do. Now we need to find all indicies of times after the start of one increment and before the start of the next increment: for (i=1:length(timeIncrements)-1) You will need to replace that number correctly. Unfortunately, I cannot tell how many ticks exist in a 5 minute increment in MATLAB, I'll arbitrarily pretend it is 123e3. Lets make a vector of times starting at 7.366965809837962e5 (your first time) and going up to 7.366966007986111e5 (your last time) in 5 minute increments. The second part is you need to break the time up into 5 minute increments. First of all, lets break the matrix in to vectors times=A(1,:) The nice thing about this problem is that you can break it into easy chunks. I have tried without success so any help is much appreciated. How can I calculate the average for column two and three per every five minutes (instead of per event)? So for the first 5 minutes 13:55:00 - 14:00:00 we should get the average value 8.225 for middle column and 3750 for the right column, i.e. Using MATLAB (R2015b) I have a time-series A that is a 4000x3 matrix.
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